EAPCET Mathematics · Intermediate first year · Paper IB
Transformation of Axes
Transformation of Axes shows how equations change when the origin is shifted or the axes are rotated, including how to remove the xy-term from a second-degree equation.
- Subject
- Mathematics
- Taught in
- Intermediate first year · Paper IB
- Mathematics in the paper
- 80 of 160 questions
Key formulas and results
- Shifting the origin to : ,
- Rotating the axes by : ,
- The -term of disappears when
- Under rotation, and stay the same (invariants)
What this chapter covers
- Translation of axes
- Rotation of axes
- Removing the first-degree and xy terms
How it is usually asked
- Find the transformed equation after a shift or rotation
- Find the angle of rotation that removes the xy-term
- Find a point’s coordinates in the new system
Understanding Transformation of Axes
Transforming the axes changes how a curve is described without moving the curve itself. In a translation the origin moves to a new point (h, k) and the axes stay parallel to the old ones, so the old and new coordinates are related by x = X + h and y = Y + k. Translation is used to remove first-degree terms and bring a conic to a simpler standard form.
In a rotation the origin stays fixed and the axes turn through an angle θ. The old coordinates are then x = X cos θ − Y sin θ and y = X sin θ + Y cos θ. Substituting these into ax² + 2hxy + by² shows that the XY-term vanishes when tan 2θ = 2h/(a − b), and when a = b the required angle is π/4.
Some quantities never change under rotation: a + b and ab − h², and for a translation the second-degree terms remain the same. These invariants let you check a transformed equation in seconds. EAPCET questions ask for the new equation after a shift, the angle that removes the xy-term, or a point’s coordinates in the new system.
Worked example
EAPCET-style question
The angle through which the axes must be rotated to remove the -term from is
- (1)
- (2)
- (3)
- (4)
Solution
- Compare with : , and , so .
- .
- So and .
- Check with invariants: the new coefficients satisfy and , giving 8 and 4, so the -term is gone.
Answer:
Common mistakes to avoid
- Taking h as the whole coefficient of xy; in ax² + 2hxy + by², h is half of it.
- Substituting x = X − h, y = Y − k when the origin is shifted to (h, k); the correct substitution is x = X + h, y = Y + k.
- Swapping the rotation formulas; old in terms of new is x = X cos θ − Y sin θ, y = X sin θ + Y cos θ.
- Expecting the constant term to stay the same under a translation; only the second-degree terms are unchanged.
How to prepare it
Use the invariants a + b and ab − h² to check a transformed equation quickly.
Once the formulas feel familiar, test them the way the exam does: practise Transformation of Axes questions chapter-wise, then attempt a full previous year paper to see whether it holds up under a 3-hour timer.
Related Mathematics chapters
- LocusIntermediate first year · Paper IB
- The Straight LineIntermediate first year · Paper IB
- Pair of Straight linesIntermediate first year · Paper IB
See every chapter in the EAPCET Mathematics syllabus.
Practise Transformation of Axes chapter-wise
Chapter-wise quizzes show exactly which topics in this chapter you still get wrong — before a full paper does.
Frequently asked questions
- Is Transformation of Axes part of the EAPCET Mathematics syllabus?
- Yes. Transformation of Axes is taught in Intermediate first year · Paper IB Mathematics, and the EAPCET Engineering syllabus is based on the Intermediate first- and second-year syllabus. Check the official notification each year for any changes.
- How should I prepare Transformation of Axes for EAPCET?
- Use the invariants a + b and ab − h² to check a transformed equation quickly.
- How many Mathematics questions are there in EAPCET?
- 80 of the 160 questions in the Engineering paper are Mathematics, spread across 37 chapters.
- What mistakes do students make in Transformation of Axes?
- Taking h as the whole coefficient of xy; in ax² + 2hxy + by², h is half of it. Substituting x = X − h, y = Y − k when the origin is shifted to (h, k); the correct substitution is x = X + h, y = Y + k. Swapping the rotation formulas; old in terms of new is x = X cos θ − Y sin θ, y = X sin θ + Y cos θ. Expecting the constant term to stay the same under a translation; only the second-degree terms are unchanged.